Matemática, perguntado por fernandagabriele91, 10 meses atrás

Me ajudemmm desesperada é pra amanha e nao sei fazer!!

Anexos:

Soluções para a tarefa

Respondido por lasouza627
0

Os cálculos são mostrados a seguir.

Explicação passo-a-passo:

Basta somar (ou subtrair) os números que estão nas mesmas posições.

a)

\left[\begin{array}{ccc}5&7\\9&4\end{array}\right] +\left[\begin{array}{ccc}6&-2\\5&8\end{array}\right] =\\\left[\begin{array}{ccc}5+6&7-2\\9+5&4+8\end{array}\right] =\left[\begin{array}{ccc}11&5\\14&12\end{array}\right]

b)

\left[\begin{array}{ccc}0&-1\\2&5\\4&1\end{array}\right] +\left[\begin{array}{ccc}11&17\\0&2\\-3&4\end{array}\right] =\\\left[\begin{array}{ccc}0+11&-1+17\\2+0&5+2\\4-3&1+4\end{array}\right] =\left[\begin{array}{ccc}11&16\\2&7\\1&5\end{array}\right]

c)

\left[\begin{array}{cccc}1&5&0&4\end{array}\right]+\left[\begin{array}{cccc}6&6&8&7\end{array}\right]=\\\left[\begin{array}{cccc}1+6&5+6&0+8&4+7\end{array}\right]=\\\left[\begin{array}{cccc}7&11&8&11\end{array}\right]

d)

\left[\begin{array}{ccc}1&1&1\\2&3&4\\-1&-2&-5\end{array}\right]-\left[\begin{array}{ccc}0&1&2\\1&1&3\\-3&-2&-7\end{array}\right]+\left[\begin{array}{ccc}4&-1&1\\0&3&-2\\2&1&3\end{array}\right]=\\\left[\begin{array}{ccc}1-0+4&1-1-1&1-2+1\\2-1+0&3-1+3&4-3-2\\-1+3+2&-2+2+1&-5+7+3\end{array}\right]=\\\left[\begin{array}{ccc}5&-1&0\\1&5&-1\\4&1&5\end{array}\right]

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