Matemática, perguntado por ulissesmuniz290, 7 meses atrás

ME AJUDEMMM!!!!!! Dadas as matrizes calcule:

Anexos:

ulissesmuniz290: me ajudaaaaaaaaaa!!!!!!!!!

Soluções para a tarefa

Respondido por dicristo2004
1

A) A+B= \left[\begin{array}{ccc}1&-3&5\\0&2&-4\end{array}\right] + \left[\begin{array}{ccc}3&1&-8\\5&1&0\end{array}\right] =\left[\begin{array}{ccc}4&-2&-3\\5&3&-4\end{array}\right]

B)A-B= \left[\begin{array}{ccc}1&-3&5\\0&2&-4\end{array}\right] - \left[\begin{array}{ccc}3&1&-8\\5&1&0\end{array}\right] =\left[\begin{array}{ccc}-2&-4&13\\-5&1&-4\end{array}\right]

C) 2A+C^t= \left[\begin{array}{ccc}2(1)&2(-3)&2(5)\\2(0)&2(2)&2(-4)\end{array}\right] + \left[\begin{array}{ccc}2&9&-3\\6&0&-1\end{array}\right]  = \left[\begin{array}{ccc}4&3&7\\6&4&-9\end{array}\right]

D) 3A+2B-C^t=\left[\begin{array}{ccc}3&-9&15\\0&6&-12\end{array}\right]+ \left[\begin{array}{ccc}6&2&-16\\10&2&0\end{array}\right]-\left[\begin{array}{ccc}2&9&-3\\6&0&-1\end{array}\right]=

\left[\begin{array}{ccc}9&-7&-1\\10&8&-12\end{array}\right]-\left[\begin{array}{ccc}2&9&-3\\6&0&-1\end{array}\right]=\left[\begin{array}{ccc}7&-16&2\\4&8&-11\end{array}\right]

E) (A+B)^t+C=\left[\begin{array}{ccc}4&5\\-2&3\\-3&-4\end{array}\right]+\left[\begin{array}{ccc}2&6\\9&0\\-3&-1\end{array}\right]=\left[\begin{array}{ccc}6&11\\7&3\\-6&-5\end{array}\right]

Espero ter ajudado. Editar em LaTeX deu um trabalho, então demorou um pouco.

Qualquer coisa, fala aí!


ulissesmuniz290: VALEUUUU!!!!!
ulissesmuniz290: Sei como é na LaTex
ulissesmuniz290: também edito por lá. obrigado!
dicristo2004: Tmj!
ulissesmuniz290: blz
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