Question

Me ajudem x²+7x+14=0
X²+5x+6=0
X²-5x+6=0
3x²-10x+3=0
10x²-7x-12=0

Answer 1

Resposta:

x²+7x+14=0

Δ= b²-4ac

Δ = 7²-4.1.14

Δ = 49-56

Δ = -7 (números negativos não tem x)

X²+5x+6=0

Δ= b²-4ac

Δ = 25-24

Δ = 1

X= -5±√1÷2

X= -5±1÷2

X'= -5+1÷2 = -4÷2 = -2

X"= -5-1÷2 = -6÷2 = -3

X²-5x+6=0

Δ= b²-4ac

Δ = 25-24

Δ = 1

X= 5±√1÷2

X= 5±1÷2

X'= 5+1÷2 = 6÷2 = 3

X"= 5-1÷2 = 4÷2 = 2

3x²-10x+3=0

Δ= b²-4ac

Δ= 100-36

Δ= 64

X= 10±√64÷6

X= 10±8÷6

X'= 10+8÷6 = 18÷6 = 3

X"= 10-8÷6 = 1/3

10x²-7x-12=0

Δ= b²-4ac

Δ= 49+480

Δ= 529

X= 7±√529÷20

X= 7±23÷20

X'= 7+23÷20 = 30/20 = 3/2

X"=  7-23÷20 = -16/20= 4/5

Demorei mas espero ter ajudado!!