Question

Me Ajudem !

X² + 4X = 0
X² - 16X = 0
X² - 8X 12 =0

Answer 1

1)

x²+4x=0
x(x+4)=0
x'→ 0
x''=-4

2 )

x²-16x=0
x(x-16)=0
x'→ 0
x''→ 16

3 )

$x^2-8x+12=0\\\Delta=(-8)^2-4.1.12\\\Delta=64-48\\\Delta=16$

$x= \frac{8\pm4}{2} \\ \\x_1=6\\ \\x_2=2$