Question

me ajudem
${x}^{2} - 10x + 25 = 0$
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Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-10x+25=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=1{;}~b=-10~e~c=25\\\\C\'alculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(-10)^{2}-4(1)(25)=100-(100)=0\\\\C\'alculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-10)-\sqrt{0}}{2(1)}=\frac{10-0}{2}=\frac{10}{2}=5\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-10)+\sqrt{0}}{2(1)}=\frac{10+0}{2}=\frac{10}{2}=5\\\\S=\{5,~5\}$