Question

Me ajudem

$- 2^{2} +( \frac{2}{3}) ^{-2}$

e

$- 2^{4} +(-3) ^{2} + 4^{0}$

Answer 1

$-4+ (\dfrac{3}{2} )^{2} =-4+ \dfrac{9}{4} = \dfrac{-16+9}{4} = -\dfrac{7}{4} \\ \\ -16+9+1=-16+10=-6$

Answer 2

-2² + (2/3)⁻² =
-2.2 + (3/2)² =
-4 + 9/4 = 
m.m.c = 4
-16 /4+ 9/4 = -7/4


-2⁴ + (- 3)² + 4°
-2.2.2.2 + (+9) + 1 =
-16 + 9 + 1 = -6