Question

Me ajudem ?

Teorema de Tales

Answer 1

Olá,

1)

$\frac{x}{14} = \frac{9}{12} \\ \\ 12x = 126 \\ x = 126 \div 12 \\ x = 10.5$

2)

$\frac{8}{x + 1} = \frac{12}{2x - 6} \\ \\ 16x - 48 = 12x + 12 \\ 16x - 12x = 12 + 48 \\ 4x = 60 \\ x = 60 \div 4 \\ x = 15$

$\frac{x - 5}{x + 1} = \frac{6}{24} \\ \\ 24x - 120 = 6x + 6 \\ 24x - 6x = 6 + 120 \\ 18x = 126 \\ x = 126 \div 18 \\ x = 7$

3)⏫⏫⏫

4)

$\frac{x}{9} = \frac{8}{12} \\ \\ 12x = 72 \\ x = 72 \div 12 = 6$

5)

$\frac{x}{2} = \frac{6}{3} \\ \\ 3x = 12 \\ x = 12 \div 3 = 4 \\ \\ \frac{2}{4} = \frac{3}{y} \\ \\ 2y = 12 \\ y = 12 \div 2 = 6$

6)

$\frac{3}{6} = \frac{x}{4} \\ \\ 6x = 12 \\ x = 12 \div 2 = 6$

$\frac{10}{y} = \frac{3}{6} \\ \\ 3y = 60 \\ y = 60 \div 3 = 20$

7)

$\frac{6}{x + 2} = \frac{5}{x} \\ \\ 6x = 5x + 10 \\ 6x - 5x = 10 \\ x = 10$

8)

$\frac{8}{24} = \frac{6}{x + 4} \\ \\ 8x + 32 = 144 \\ 8x = 144 - 32 \\ 8x = 112 \\ x = 112 \div 8 = 14$

9)

$\frac{9}{x} = \frac{12}{x + 2} \\ \\ 9x + 18 = 12x \\ 9x - 12x = - 18 \\ - 3x = - 18 \\ x = - 18 \div - 3 \\ x = 6$

10)

$\frac{x}{10} = \frac{x + 3}{15} \\ \\ 10x + 30 = 15x \\ 10x - 15x = - 30 \\ - 5x = - 30 \\ x = - 30 \div - 5 \\ x = 6$

11)

$\frac{18}{x} = \frac{15}{5} \\ \\ 15x = 90 \\ x = 90 \div 15 = 6$

$\frac{6}{y} = \frac{5}{10} \\ \\ 5y = 60 \\ y = 60 \div 5 \\ y = 12$

12)

$\frac{12}{21} = \frac{2x - 2}{3x + 3} \\ \\ 36x + 36 = 42x - 42 \\ 36x - 42x = - 42 - 36 \\ - 6x = - 78 \\ x = - 78 \div - 6 \\ x = 13$

13) Falta um valor.

14)

$\frac{10}{15} = \frac{3x + 1}{5x - 2} \\ \\ 50x - 20 = 45x + 15 \\ 50x - 45x = 15 + 20 \\ 5x = 35 \\ x = 35 \div 5 = 7$

15)

$\frac{9}{12} = \frac{x}{x + 2} \\ \\ 9x + 18 = 12x \\ 9x - 12x = - 18 \\ - 3x = - 18 \\ x = - 18 \div - 3 \\ x = 6$

16)

$\frac{2x - 4}{21} = \frac{3x}{35} \\ \\ 63x = 70x - 140 \\ 63x - 70x = - 140 \\ - 7x = - 140 \\ x = - 140 \div - 7 \\ x = 20$

17)

$\frac{x}{28 } = \frac{5}{14} \\ \\ 14x = 140 \\ x = 140 \div 14 = 10$

18)

$\frac{1}{2x} = \frac{x}{4} \\ \\ 2 {x}^{2} = 4 \\ {x}^{2} = 4 \div 2 \\ {x}^{2} = 2 \\ x = \sqrt{2}$

Espero ter ajudado :-)