Question

Me ajudem só 5 questões . A) ( t - 7 ) elevado a 2 B) (10 + w) ( 10-w) C) (12 - H ) elevado a 2 D) ( 11 + N) elevado a 2 E) (13 + J) ( 13 - J ) Obs: Produtos notáveis

Answer 1

Oie, Td Bom?!

A)

$= (t - 7) {}^{2}$

$= t {}^{2} - 2t \: . \: 7 + 7 {}^{2}$

$= t {}^{2} - 14t + 49$

B)

$= (10 + w) \: . \: (10 - w)$

$= 10 {}^{2} - w {}^{2}$

$= 100 - w {}^{2}$

C)

$= (12 - h) {}^{2}$

$= 12 {}^{2} - 2 \: . \: 12h + h {}^{2}$

$= 144 - 24h + h {}^{2}$

$= h {}^{2} - 24h + 144$

D)

$= (11 + n) {}^{2}$

$= 11 {}^{2} + 2 \: . \: 11n + n {}^{2}$

$= 121 + 22n + n {}^{2}$

$= n {}^{2} + 22n + 121$

E)

$= (13 + j) \: . \: (13 - j)$

$= 13 {}^{2} - j {}^{2}$

$= 169 - j {}^{2}$

Att. Makaveli1996

Answer 2

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https://brainly.com.br/tarefa/31053910

$\tt{a)}~\sf{(t-7)^2=t^2-14t+49}\\\tt{b)}~\sf{(10+w)(10-w)=100-w^2}\\\tt{c)}~\sf{(12-h)^2=144-24h+h^2}\\\tt{d)~\sf{(11+n)^2=121+22n+n^2}$

$\tt{e)}~\sf{(13+j)(13-j)=169-j^2}$