Question

me ajudem se puderem.

Answer 1

R: Letra  A

veja

$p(x)=-3 x^{2} +x+4k$

para x=$\frac{1}{3}$

$-3( \frac{1}{3} )^2+ \frac{1}{3} +4k=1$

$-3( \frac{1}{9} )+ \frac{1}{3} +4k=1$

$- \frac{1}{3} + \frac{1}{3} +4k=1$

$4k=1$

$k= \frac{1}{4}$