Question

me ajudem, resolva as seguintes equações exponenciais: 3 elevado a x-5=27 elevado a 1-x

Answer 1

$i$

$3^{x-5} =27^{1-x}$

$3^{x-5} =3^3^{(1-x)}$

$x-5 =3-3x$

$4x=8$

$\boxed {x=2}$

Answer 2

$3^{x - 5}=27^{1 - x}\\\\3^{x-5}=(3^{3} )^{1-x}\\\\Bases-iguais-elimina\\\\x-5=3* (1 - x)\\\\x-5 = 3 - 3x\\\\ 3x + x = 5+3\\\\ 4x=8\\\\ x = 8 : 4\\\\x=2$