me ajudem,
QUESTAO 16- Aplicando as propriedades transforme numa so poténcia as expressões
Anexos:
![](https://pt-static.z-dn.net/files/dd9/1f4d6209bd206977919d01dd91bbe7af.jpg)
Soluções para a tarefa
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Olá!
Lembrando as propriedades:
![x ^{m} \times \: \: x ^{n} = {x}^{m + n} x ^{m} \times \: \: x ^{n} = {x}^{m + n}](https://tex.z-dn.net/?f=x+%5E%7Bm%7D++%5Ctimes++%5C%3A++%5C%3A+x+%5E%7Bn%7D++%3D++%7Bx%7D%5E%7Bm+%2B+n%7D+)
![{x}^{m} \div {x}^{n} = {x}^{m - n} {x}^{m} \div {x}^{n} = {x}^{m - n}](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7Bm%7D++%5Cdiv++%7Bx%7D%5E%7Bn%7D++%3D++%7Bx%7D%5E%7Bm+-+n%7D+)
![( {x}^{m} )^{n} = {x}^{m \: \times \: n} ( {x}^{m} )^{n} = {x}^{m \: \times \: n}](https://tex.z-dn.net/?f=%28+%7Bx%7D%5E%7Bm%7D+%29%5E%7Bn%7D++%3D++%7Bx%7D%5E%7Bm++%5C%3A+%5Ctimes++%5C%3A+n%7D+)
Agora iremos aplicar essas propriedades, veja:
![a) \: {x}^{2} . \: x \: . \: {x}^{8} . \: {x}^{3} = {x}^{2 + 1 + 8 + 3} = {x}^{13} a) \: {x}^{2} . \: x \: . \: {x}^{8} . \: {x}^{3} = {x}^{2 + 1 + 8 + 3} = {x}^{13}](https://tex.z-dn.net/?f=a%29+%5C%3A++%7Bx%7D%5E%7B2%7D++++.+%5C%3A+x+%5C%3A++.++%5C%3A+%7Bx%7D%5E%7B8%7D++++.+%5C%3A++%7Bx%7D%5E%7B3%7D++%3D++%7Bx%7D%5E%7B2+%2B+1+%2B+8+%2B+3%7D++%3D++%7Bx%7D%5E%7B13%7D+)
![b) \: {x}^{12} \div {x}^{9} = {x}^{12 - 9} = {x}^{3} b) \: {x}^{12} \div {x}^{9} = {x}^{12 - 9} = {x}^{3}](https://tex.z-dn.net/?f=b%29+%5C%3A++%7Bx%7D%5E%7B12%7D++%5Cdiv++%7Bx%7D%5E%7B9%7D++%3D++%7Bx%7D%5E%7B12+-+9%7D++%3D++%7Bx%7D%5E%7B3%7D+)
![c) \: {(x}^{5} )^{4} = {x}^{5 \times 4} = {x}^{20} c) \: {(x}^{5} )^{4} = {x}^{5 \times 4} = {x}^{20}](https://tex.z-dn.net/?f=c%29+%5C%3A++%7B%28x%7D%5E%7B5%7D+%29%5E%7B4%7D++%3D++%7Bx%7D%5E%7B5+%5Ctimes+4%7D++%3D++%7Bx%7D%5E%7B20%7D+)
![d) \: a \: . \: {a}^{7} . \: {a}^{2} = {a}^{1 + 7 + 2} = {a}^{10} d) \: a \: . \: {a}^{7} . \: {a}^{2} = {a}^{1 + 7 + 2} = {a}^{10}](https://tex.z-dn.net/?f=d%29+%5C%3A+a+%5C%3A+.+%5C%3A++%7Ba%7D%5E%7B7%7D+.+%5C%3A++%7Ba%7D%5E%7B2%7D++%3D++%7Ba%7D%5E%7B1+%2B+7+%2B+2%7D++%3D++%7Ba%7D%5E%7B10%7D+)
![e) \: {p}^{4} . \: {p}^{3} = {p}^{4 + 3} = {p}^{7} e) \: {p}^{4} . \: {p}^{3} = {p}^{4 + 3} = {p}^{7}](https://tex.z-dn.net/?f=e%29+%5C%3A++%7Bp%7D%5E%7B4%7D+.+%5C%3A++%7Bp%7D%5E%7B3%7D++%3D++%7Bp%7D%5E%7B4+%2B+3%7D++%3D++%7Bp%7D%5E%7B7%7D+)
Lembrando as propriedades:
Agora iremos aplicar essas propriedades, veja:
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