Question

me ajudem, quando o delta não tiver raiz exata oque acontece? x''-6+6x=0

Answer 1

Continue os cálculos normalmente

$x^2-6+6x=0\\ \\\Delta=b^2-4ac\\ \\\Delta=6^2-4.1.(-6)\\ \\\Delta=60$

$x= \frac{-b\pm \sqrt{\Delta} }{2a} \\ \\x= \frac{-6\pm \sqrt{60} }{2} \\ \\x= \frac{-6\pm \sqrt{2^2*15} }{2} \\ \\x= \frac{-6\pm2 \sqrt{15} }{2} \\ \\\boxed{x'= -3+ \sqrt{15} }\\ \\\boxed{x''=-3- \sqrt{15} }$