Question

ME AJUDEM PVF
1) Construa o gráfico das seguintes funções quadráticas:
a) f(x)= x^2, sendo o Domínio: {-3, -2,-1,0,1,2,3}
b) f(x)= x^2+2, sendo o Domínio: {-2,-1,0, 1, 2}
c) f(x)= -2X^2 +4x, sendo o Domínio: {-1,0, 1, 2, 3}
obs ^ siginifica elevado a tal numero​

Answer 1

Os gráficos estão em anexo.

a)

$\boxed{f(x)=x^2}$

$x=-3\ \to\ f(-3)=(-3)^2=9\ \to\ \boxed{A(-3,9)\in f(x)}$

$x=-2\ \to\ f(-2)=(-2)^2=4\ \to\ \boxed{B(-2,4)\in f(x)}$

$x=-1\ \to\ f(-1)=(-1)^2=1\ \to\ \boxed{C(-1,1)\in f(x)}$

$x=0\ \to\ f(0)=(0)^2=0\ \to\ \boxed{D(0,0)\in f(x)}$

$x=1\ \to\ f(1)=(1)^2=1\ \to\ \boxed{E(1,1)\in f(x)}$

$x=2\ \to\ f(2)=(2)^2=4\ \to\ \boxed{F(2,4)\in f(x)}$

$x=3\ \to\ f(3)=(3)^2=9\ \to\ \boxed{G(3,9)\in f(x)}$

b)

$\boxed{f(x)=x^2+2}$

$x=-2\ \to\ f(-2)=(-2)^2+2=6\ \to\ \boxed{A(-2,6)\in f(x)}$

$x=-1\ \to\ f(-1)=(-1)^2+2=3\ \to\ \boxed{B(-1,3)\in f(x)}$

$x=0\ \to\ f(0)=(0)^2+2=2\ \to\ \boxed{C(0,2)\in f(x)}$

$x=1\ \to\ f(1)=(1)^2+2=3\ \to\ \boxed{D(1,3)\in f(x)}$

$x=2\ \to\ f(2)=(2)^2+2=6\ \to\ \boxed{E(2,6)\in f(x)}$

c)

$\boxed{f(x)=-2x^2+4x}$

$x=-1\ \to\ f(-1)=-2(-1)^2+4(-1)=-6\ \to\ \boxed{A(-1,-6)\in f(x)}$

$x=0\ \to\ f(0)=-2(0)^2+4(0)=0\ \to\ \boxed{B(0,0) \in f(x)}$

$x=1\ \to\ f(1)=-2(1)^2+4(1)=2\ \to\ \boxed{C(1,2)\in f(x)}$

$x=2\ \to\ f(2)=-2(2)^2+4(2)=0\ \to\ \boxed{D(2,0)\in f(x)}$

$x=3\ \to\ f(3)=-2(3)^2+4(3)=-6\ \to\ \boxed{E(3,-6)\in f(x)}$