Question

Me ajudem, preciso dos cálculos

a) (4/2)+6²-8+12÷4-4²+(10)²
b) (-3/6)³-20+35÷(-7)+3÷3
c) (-12)²+30÷3-18+6-4×(8)³

Answer 1

a)

$( \frac{4}{2} ) + {6}^{2} - 8 + 12 \div 4 - {4}^{2} + \\ {(10)}^{2} = > \\ (\frac{4}{2} ) + 36 - 8 + 3 - 16 + 100 = >$

$( \frac{4}{2}) + 115 = > \frac{4}{2} + \frac{115}{1} = > \\ \frac{4 + 230}{2} = > \frac{234}{2} = > 117$

b)

$( { \frac{ - 3}{6} })^{3} - 20 + 35 \div ( - 7) + 3 \div 3 = > \\ ( \frac{ - 27}{216} ) - 20 + ( - 5) + 1 = >$

$( \frac{ - 27}{216} ) - 20 - 5 + 1 = > \\ (\frac{ - 27}{216} ) - 24 = > ( \frac{ - 27}{216} ) - \frac{24}{1}$

$\frac{( - 27) - 5184}{216} = > \frac{ - 5211}{216} = > - 24.125$

c)

$( { - 12)}^{2} + 30 \div 3 - 18 + 6 - 4 \\ \times ( {8)}^{3} = > \\ 144 + 10 - 18 + 6 - 4 \times 512$

$144 + 10 - 18 + 6 - 2048 = > \\ 154 - 18 - 2046 2 = > 2006$

Espero ter ajudado