Question

me ajudem ( preciso do calculo)


4x-4-2x=-6-x+8
a)-3
b)-2
c)+2
d)+3

2x-1+6x=-4-x+1
a)
$+ \frac{2}{9}$
b)
$- \frac{2}{9}$
c)
$- \frac{9}{2}$
d)
$+ \frac{9}{2}$

3(x-1)=2(x+1)
a)0
b)1
c)2
d)5

Answer 1

$4x-4-2x=-6-x+8 \\ \\ 4x-2x+x=-6+8+4 \\ \\ 3x=6 \\ \\ x=\frac{6}{3} \\ \\ x=2$

C

_____________

$2x-1+6x=-4-x+1 \\ \ 2x+6x+x=-4+1+1 \\ \\ 9x=-2 \\ \\ x=-\frac{2}{9}$

B

_____________

$3(x-1)=2(x+1) \\ \\ 3x-3=2x+2 \\ \\ 3x-2x=2+3\\ \\ x=5$

D