Question

Me ajudem preciso agr '-''

Answer 1

$p(t) = 40 \times e^{0,02t}\\\\40 \times e^{0,02t} > 240\\e^{0,02t} > \frac{240}{40}\\In(e^{0,02t}) > In6\\0,02t \times Ine > In6\\0,02t \times 1 > 1,8\\t > \frac{1,8}{0,02}\\t > 90\\\\1940 + 90 = 2030$