Question

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Answer 1

$CO+2H_2$ ⇆ $CH_3OH$

$M_{CO} = 12 \times 1 + 16 = 28g/mol\\M_{2H_2} = 4 \times 1 = 4g/mol\\M_{CH_3OH} = 1 \times 12 + 4 \times 1 + 1 \times 16 = 32g/mol$

28g     ------   32g

 x        ------    230g  

32x = 230*28

x = 6440 / 32

x = 201,25g

4g      --------   32g

y         --------  230g  

32y = 230 * 4

y = 920 / 32

y = 28,75

g

São 201,25g de monóxido de carbono e 28,75g de hidrogênio molecular.