Question

me ajudem porfavor, limite x--> 1 $\frac{\sqrt{5x+4 }-3 }{\sqrt[3]{x-2} +1}$ preciso pra hoje

Answer 1

Resposta:

$limite = \frac{\sqrt{5.1+4} -3}{\sqrt[3]{1-2}+1 } = \frac{\sqrt{9} -3}{\sqrt[3]{-1}+1 } =\frac{0}{\sqrt[3]{-1}+1} = 0$