Question

me ajudem por favor!

x²+12x-27=0

alguém sabe resolver??​

Answer 1

Utilizando a Fórmula de Bhaskara, temos que a = 1, b = 12 e c = - 27:

$\Delta=b^2-4\cdot a\cdot c\\\Delta=12^2-4\cdot1\cdot(-27)\\\Delta=144+108\\\Delta=252\\ \\x=\frac{-b\pm\sqrt{\Delta}}{2\cdot a}\\ \\Sendo\;\sqrt{252}=\sqrt{36\cdot7}=6\sqrt{7}\\ \\x=\frac{-12\pm6\sqrt{7}}{2\cdot1}\\ \\\boxed{x'=\frac{-12+6\sqrt{7}}{2}}\\ \\\boxed{x''=\frac{-12-6\sqrt{7}}{2}}$

Bons estudos!