Question

me ajudem por favor só responda se souber ​

Answer 1

Resposta:

Aplicando o teorema de Pitágoras:

${h}^{2} = {a}^{2} + {b}^{2}$

Diagonal do quadrado:

$d = l \sqrt{2} \\ \\ d = 8 \sqrt{2} \times \sqrt{2} \\ \\ d = 8 \times \sqrt{2 \times 2} \\ \\ d = 8 \times \sqrt{4} \\ \\ d = 8 \times 2 \\ \\ d = 16 \: cm$

Triângulo equilatero todos os lados iguais:

Logo, temos que:

Perímetro = 3(lado)

P = 3L

21 = 3L

L = 21/3

L = 7 cm

${7}^{2} = {h}^{2} + (\frac{7 }{2} ) {}^{2} \\ \\ ({h}^{2} = 49 - \frac{49}{4} ) \times 4 \\ \\ 4 {h}^{2} = 196 - 49 \\ \\ {h}^{2} = \frac{147}{4} \\ \\ </strong></p><p><strong>h</strong><strong>=</strong><strong> </strong><strong>\sqrt{</strong><strong>\frac{147}{4} </strong><strong>} </strong><strong>=</strong><strong>></strong></p><p><strong>h</strong><strong> </strong><strong>=</strong><strong> \frac{</strong><strong>7</strong><strong>\sqrt{3} </strong><strong>}{</strong><strong>2</strong><strong>} </strong><strong>(</strong><strong>c</strong><strong>m</strong><strong>)</strong><strong> </strong><strong><</strong><strong>o</strong><strong>u</strong><strong>></strong></p><p></p><p></p><p></p><p><strong>h = \sqrt{36.75} \\ \\ h = 6.06 \: cm$

Bons Estudos!