Question

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Answer 1

$\sqrt{x}= 1+\sqrt{3}==>(\sqrt{x})^2= (1 + \sqrt{3})^2$

$x = 1 + 2\sqrt{3} + 3 ==> x = 4+2\sqrt3$

$x^2 = (4+2\sqrt3 )^2\\x^2 = 16 + 16\sqrt3 + 12\\x^2 = 28 + 16\sqrt3$

Alternativa (A)