Question

me ajudem por favor pra eu fazer

Answer 1

a) $\frac{12}{x}= \frac{8}{6} => 8x=12*6 => 8x=72 => x= \frac{72}{8} => x=9 \\ \frac{y}{8}= \frac{8}{6} => 6y=8*8 => 6y=64 => y= \frac{64}{6} => y= \frac{32}{3}$

b) $\frac{2+y}{8}= \frac{6}{4} => 4(2+y)=6*8 => 8+4y=48 => 4y=40 => y=10 \\ \frac{x+8}{y}= \frac{6}{4} => 4(x+8)=6y => 4x+32 = 60 => 4x = 28 => x=7$