Question

me ajudem por favor não consigo resolver​

Answer 1

a)

$f(x)=\frac{-3}{4} x+m$

$f(-8)=-4$ então $x=-8$ e $y=-4$ substituindo:

$-4=\frac{-3}{4} .(-8)+m$

$-4=\frac{24}{4}+m$

$-4=6+m$

$-4-6=m$

$-10=m$

$m=-10$

b)

$f(1)=\frac{-3}{4} .1-10$

$f(1)=\frac{-3}{4} -10$

$f(1)=\frac{-3-40}{4}$

$f(1)=\frac{-43}{4}$

c)$f(x)=-12$

$f(x)=\frac{-3}{4} x-10$

$-12=\frac{-3}{4} x-10$

$-12+10=\frac{-3}{4} x$

$-2=\frac{-3}{4} x$

$-2*4=-3. x$

$-8=-3. x$

$\frac{-8}{-3} =x$

$\frac{8}{3} =x$

$x=\frac{8}{3}$