Question

Me ajudem por favor. Não consegui resolver
✓2x-16
✓a+3-✓b+1
✓x-9 /y+6

Answer 1

$\sqrt{2x-16} =0 \\ (\sqrt{2x-16})^2 =0^2 \\ 2x-16=0 \\ 2x=16 \\ x=16/2 \\ x=8$

$\sqrt{a+3} - \sqrt{b+1} =0 \\ \sqrt{a+3}=\sqrt{b+1} \\ (\sqrt{a+3})^2=(\sqrt{b+1})^2 \\ a+3=b+1 \\ a-b=1-3 \\ a-b=-2 \\ Resolvendo \ para \ a \\ a=b-2 \\ Resolvendo \ para \ b \\ -b=-a-2 \ \ (-1) \\ b=a+2$

$\frac{ \sqrt{x-9} }{y+6} =0 \\ \\ \sqrt{x-9}=0 \\ (\sqrt{x-9})^2=0^2 \\ x-9=0 \\ x=9 \\ \\ y+6 \neq 0 \\ y \neq -6$