Question

Me ajudem por favor, imagem em anexo. 25 PONTOS!!!

Answer 1

$2^{a} . 3^{b} . 5^{c} . 7^{d} = ( 2^{a} . 3^{b} . 5^{c} . 7^{d})^2 = 2^{2a} . 3^{2b} . 5^{2c} . 7^{2d}$  
      
2³ . 3 . 7² ¨¨¨¨¨¨¨¨ (2³.3.7²)² = $2^{6} . 3^2 . 7^4$

$2^5 . 3^2 . 5 = (2^5.3^2.5)^2 = 2^1^0 . 3^4 . 5^2$

                     

Answer 2

p--->2³.3.7²
n=p²---->2^6.3^2. 7^4

p---->2^5.3^2.5
n=p²--->2^10.3^4.5^2

p---->2^a.3^b.5^c.7^d
n=p²--->2^2a.3^2b.5^2c.7^2d