Question

me ajudem por favor, equação do segundo grau. teoria de Bhaskara​

Answer 1

e) 4x²-20x+25=0

a=4, b=-20, c=25

∆=b²-4ac

∆=(-20)²-4.4.25

∆=400-400

∆=0

x=-b±√∆/2a

x=20±√0/2.4

x=20±0/8

x=20/8=10/4=5/2

S={5/2}

f)2x²+7x+6=0

a=2, b=7, c=6

∆=b²-4ac

∆=7²-4.2.6

∆=49-48

∆=1

x=-b±√∆/2a

x=-7±√1/2.2

x=-7±1/4

x1=-7+1/4=-6/4=-3/2

x2=-7-1/4=-8/4=-2

S={-2,-3/2}

g)x²-3x-10=0

a=1, b=-3, c=-10

∆=b²-4ac

∆=(-3)²-4.1.(-10)

∆=9+40

∆=49

x=-b±√∆/2a

x=3±√49/2.1

x=3±7/2

x1=3+7/2=10/2=5

x2=3-7/2=-4/2=-2

S={-2,5}

h)x²+9x+14=0

a=1, b=9, c=14

∆=b²-4ac

∆=9²-4.1.14

∆=81-56

∆=25

x=-b±√∆/2a

x=-9±√25/2.1

x=-9±5/2

x1=-9+5/2=-4/2=-2

x2=-9-5/2=-14/2=-7

S={-7,-2}

i)x²+14x+49=0

a=1, b=14, c=49

∆=b²-4ac

∆=14²-4.1.49

∆=196-96

∆=100

x=-b±√∆/2a

x=-14±√100/2.1

x=-14±10/2

x1=-14+10/2=-4/2=-2

x2=-14-10/2=-24/2=-12

S={-12,-2}

j)x²-9x+20=0

a=1, b=-9, c=20

∆=b²-4ac

∆=(-9)²-4.1.20

∆=81-80

∆=1

x=-b±√∆/2a

x=9±√1/2.1

x=9±1/2

x1=9+1/2=10/2=5

x2=9-1/2=8/2=4

S={4,5}