Question

Me ajudem por favor é urgente!!

Answer 1

Resolução (passo-a-passo)

$a) \: {2}^{4} =$

$(2).(2).(2).(2) = 16$

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$b) \: {2}^{ - 3} =$

$(\frac{1}{2})^{3} =$

$(\frac{1}{2}).(\frac{1}{2}).(\frac{1}{2}) = \frac{1}{8}$

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$c) \: ({ - 4})^{3} =$

$( - 4).( - 4).( - 4) = - 64$

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$d) \: {10}^{ - 3} =$

$( \frac{1}{10}) ^{3} = ( \frac{1}{10}).( \frac{1}{10}). ( \frac{1}{10}) = \frac{1}{1000}$

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$e) ( - \frac{3}{7})^{ - 2}$

$( - \frac{7}{3})^{2} =$

$( - \frac{7}{3}).( - \frac{7}{3}).( - \frac{7}{3}) = - \frac{343}{27}$

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$f) \: {0}^{10} = 0$

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$g) ( \frac{1}{2})^{ - 3} =$

$(2) ^{3} = (2).(2).(2) = 8$

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$h)( - 1) ^{15} = - 1$

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$i)( - 1)^{100} = 1$

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$j)(0,181818...) ^{0} = 1$

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2)

$a) \frac{2^{4}. \: 2^{10}. \: 2^{3}}{2^{5} \: . \: 2^{6}} =$

$\frac{2^{4 + 10 + 3}}{2^{5 + 6}} =\frac{2^{17}}{2^{11}}$

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$b) ( {7.4})^{2} =$

$( {28})^{2} = 784$

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$c)( {7}^{5}: {7}^{3}).7 =$

$( {7}^{5 - 3}).7 =$

${7}^{2}.7 =$

${7}^ {2 + 1} = {7}^{3}$

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$d) (( - \frac{1}{2} )^{3} )^{2} =$

$( - \frac{1}{2} )^{6} =$

$( \frac{1}{64} )$

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