Question

me ajudem por favor é URGENTE​

Answer 1

11/2

$\sf {\Huge ——————— }$

$\sf \huge \green{ \frac{\frac{1}{3} + \frac{2}{5}}{\frac{1}{3} \times \frac{2}{5} } } = \sf \red{ \frac{\frac{11}{\diagdown\!\!\!\!\!1\!5}}{\frac{2}{\diagdown\!\!\!\!\!1\!5}} }= \sf \orange{ \frac{11}{2}}$

Answer 2

Resposta:

$\:\:\:\:\:\: \pink h\pink o\pink o\blue i\blue l\blue \: \green v\green a\green m\green o\green s\green \: \orange l\orange á\orange .\green .\green .\green \:$

Explicação passo-a-passo:

$\rm \: temos \: \frac{a + b}{a \times b} \: para \: < \frac{a = \frac{1}{3} }{b = \frac{2}{5} }$

$\rm \: substituimos \: \frac{a + b}{a \times b} \: por \: a = \frac{1}{3} \: \\ \\ \rm \: e \: b = \frac{2}{5}$

$\rm \: assim \: calculamos : \\ \\ = \frac{\frac{1}{3} + \frac{2}{5} }{ \frac{1}{3} \times \frac{2}{5} } = \frac{11}{2} \\ \\ \rm \: no \: qual \: simplificamos \: e \: temos : \\ \\ \rm \: = \frac{11}{2}$

$\\ \\ \tt \: caso \: queiras \: o \: calculo \: \\ \tt \: completo :$

$\rm \: temos : \frac{ \frac{1}{3} + \frac{2}{5} }{ \frac{1}{3} \times \frac{2}{5} } = \: \\ \\ \rm \: pegamos \: = \frac{1}{3} + \frac{2}{5} = \frac{11}{15}$

$\rm \: assim \: temos : \frac{ \frac{11}{15} }{ \frac{1}{3} \times \frac{2}{5} }$

$\rm \: agora \: aplicamos \: a \: \\ \rm \: propriedade \: de \: frações \: \\ \rm \: \frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d} \\ \rm \: e \: temos :$

$\rm \: \frac{1}{3} \times \frac{2}{5} = \frac{1 \times 2}{3 \times 5} = > { \frac{ \frac{11}{15} }{ \frac{1 \times 2}{3 \times 5} } }$

$\rm \: multiplicamos \: 1 \times 2 = 2 : \\ \\ \rm \: = \frac{ \frac{11}{15} }{ \frac{2}{3\times 5} }$

$\rm \: agora \: multiplicamos \: \\ \rm \: 3 \times 5 = 15: \\ \\ \rm \: = \frac{ \frac{11}{15} }{ \frac{2}{15} }$

$\rm \: agora \: aplicamos \: novamente \\ \rm \: propriedades \: de \: frações \: \\ \rm \: \frac{ \frac{a}{b} }{ \frac{c}{d} } = \frac{a \times d}{b \times c} \\ \rm \: e \: temos :$

$\rm \: e \: temos : \\ \\ \rm \: = \frac{11 \times 15}{15 \times 2}$

$\rm \: cortamos \: o \: fator \: comum \\ \rm \: que \: e \: 15 \: e \: temos \: a \\ \rm \: resposta : \\ \\ \rm \: = \frac{11}{2}$

$\rm \: no \: qual \: temos \: a \: resposta \\ \rm \: correta \: = \frac{11}{2}$

$\\ \\ \\ \\ \:\:\:\:\:\:\: \green e\green s\green p\green e\green r\green o\green \: \pink t\pink e\pink r\pink \: \orange a\orange j\orange u\orange d\orange a\orange d\orange o\orange \: \purple . \\ \\ \\ \:\:\: \blue b\blue o\blue n\blue s\blue \: \red e\red s\red t\red u\red d\red o\red s\red \: \green .$$\\ \\ \\ \:\:\:\: \green a\blue s\pink s\orange : \blue m\blue \alpha\blue r\blue c\blue o\: \red d\red i\red \alpha\red z\:\pink t\pink r\pink \gamma\orange s\orange t\orange \gamma\: \blue .$