Question

Me ajudem por favor é pra hj​

Answer 1

Explicação passo a passo:

2)

$\sqrt{32} +\sqrt{8} +\sqrt{18} =\\ \\ \sqrt{2^4.2} +\sqrt{2^2.2} +\sqrt{2.3^2} =\\ \\ 2^2\sqrt{2}+2\sqrt{2} +3\sqrt{2} =\\ \\ (4+2+3)\sqrt{2} =\\ \\ 9\sqrt{2} \to~letra~~d$

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3)

$2\sqrt{3} +2\sqrt{12} -3\sqrt{27} =\\ \\ 2\sqrt{3} +2\sqrt{2^2.3} -3\sqrt{3^2.3} =\\ \\ 2\sqrt{3} +2.2\sqrt{3} -3.3\sqrt{3} =\\ \\ 2\sqrt{3} +4\sqrt{3} -9\sqrt{3} =\\ \\ (2+4-9)\sqrt{\\3} =\\ \\ -3\sqrt{3} \to~~letra ~C$

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4)

$2\sqrt{3} +5\sqrt{12} -3\sqrt{27} =\\ \\ 2\sqrt{3} +5\sqrt{2^2.3} -3\sqrt{3^2.3} =\\ \\ 2\sqrt{3} +5.2\sqrt{3} -3.3\sqrt{3} =\\ \\ 2\sqrt{3} +10\sqrt{3} -9\sqrt{3} =\\ \\ (2+10-9)\sqrt{3} =\\ \\ 3\sqrt{3} \to~letra~~A$

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5)

$\sqrt{32+\sqrt{14+\sqrt{1+\sqrt{9} } } } =\\ \\ \sqrt{32+\sqrt{14+\sqrt{1+3} } } =\\ \\ \sqrt{32+\sqrt{14+\sqrt{4} } } =\\ \\ \sqrt{32+\sqrt{14+2} } =\\ \\ \sqrt{32+\sqrt{16} } =\\ \\ \sqrt{32+4} =\\ \\ \sqrt{36} =6\to~letra~~A$