Question

Me ajudem por favor é pra amanhã

Answer 1

Olá!
3) (a) ab + ac + 10b +10c
ab + ac + 10b + 10c
a(b+c) + 10(b+c)
(b+c)(a+10)

(b) xy + 2x + 5y + 10
xy + 2x + 5y + 10
x(y+2) + 5(y+2)
(y+2)(x+5)

(c) ab - 3a - 4b + 12
ab - 3a - 4b + 12
a(b-3) - 4(b-3)
(b-3)(a-4)

(d) a^2 - a + x - ax
a^2 - a + x -ax
a(a-1) - x(a-1)
(a-1)(a-x)

(e) 10a^3b - 5ab^3 + 6a^2 - 3b^2
10a^3b - 5ab^3 + 6a^2 - 3b^2
5ab(2a^2 - b^2) + 3(2a^2 - b^2)
(2a^2 - b^2)(5ab + 3)


4) (a) ax - ay + bx - by
ax - ay + bx - by
a(x-y) + b(x-y)
(a+b)(x-y)

(b) x^2 + 5x + ax + 5a
x^2 + 5x + ax + 5a
x(x+5) + a(x+5)
(x+5)(x+a)

(c) t^3 + t^2 - 7t - 7
t^3 + t^2 - 7t - 7
t^2(t+1) -7(t+1)
(t + 1)(t^2 - 7)

(d) 2b^2 + 2 - b^2k - k
2b^2 + 2 - b^2k - k
-k(b^2 + 1) + 2(b^2 + 1)
(b^2 + 1)(-k+2)

(e) a^5 + a^3 + 2a^2 + 2
a^5 + a^3 + 2a^2 + 2
a^3(a^2 + 1) + 2(a^2 + 1)
(a^2 + 1)(a^3 + 2)

(f) 5ax - 5ay + bx - by
5ax - 5ay + bx - by
5a(x-y) + b(x-y)
(x-y)(5a+b)

(g) 6a^2 + 2ab -3ac - bc
6a^2 + 2ab -3ac - bc
2a(3a + b) -c(3a + b)
(3a+b)(2a-c)

(h) x^4 - x^3 - 9x + 9
x^4 - x^3 - 9x + 9
x^3(x-1) - 9(x-1)
(x-1)(x^3-9)

(i) bx^2 - 2by + 5x^2 - 10y
x^2(b+5) - 2y(b+5)
(b+5)(x^2-2y)

(j) cx + x + 2c + 2
x(c+1) + 2(c+1)
(c+1)(x+2)


5) (a) x^2 - 81
x^2 - 81
x^2 - 9^2
(x+9)(x-9)

(b) 100 - a^2
100 - a^2
10^2 - a^2
(10+a)(10-a)

(c) 1 - m^2n^2
1 - m^2n^2
1^2 - (mn)^2
(1+mn)(1-mn)

(d) 16x^2 - 9y^2
16x^2 - 9y^2
4^2 x^2 - 3^2 y^2
(4x)^2 - (3y)^2
(4x + 3y)(4x - 3y)

(e) 49h^2 - 81p^2
49h^2 - 81p^2
7^2 h^2 - 9^2 p^2
(7h)^2 - (9p)^2
(7h+9p)(7h-9p)

(f) 100x^2 -49a^2 b^2
100x^2 -49a^2 b^2
10^2 x^2 - 7^2 a^2 b^2
(10x)^2 - (7ab)^2
(10x + 7ab)(10x - 7ab)


(6) 3x + xa^2 + 7a^2 + 21
3x + xa^2 + 7a^2 + 21
a^2(x+7) + 3(x+7)
(x+7)(a^2+3)


Espero ter ajudado!!!