Question

me ajudem, por favor!
com cálculo

a) (3x²+112x): (3x) =

b) (7x²+28 +14) : 2 =

c) (24x³ + 12x²) : (4x²) =

d) (18 a²b²? - 12 ab² +6 a²b²):(ab²) =​

Answer 1

Explicação passo-a-passo:

a)

$(3x^2+112x)\div(3x)=\dfrac{3x^2}{3x}+\dfrac{112x}{3x}=x+\dfrac{112}{3}$

b)

$(7x^2+28x+14)\div2=\dfrac{7x^2}{2}+\dfrac{28x}{2}+\dfrac{14}{2}=3,5x^2+14x+7$

c)

$(24x^3+12x^2)\div(4x^2)=\dfrac{24x^3}{4x^2}+\dfrac{12x^2}{4x^2}=6x+3$

d)

$(18a^2b^2-12ab^2+6a^2b^2)=\dfrac{18a^2b^2}{ab^2}-\dfrac{12ab^2}{ab^2}+\dfrac{6a^2b^2}{ab^2}=18a-12+6a=24a-12$