Me ajudem por favor a calcular a distancia entre os pontos
A (-2,4) e B (3,4)
A (2,3) e B (5,1)?
Soluções para a tarefa
Respondido por
1
Usaremos a seguinte fórmula:
![d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2} d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}](https://tex.z-dn.net/?f=d+%3D++%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%7D+)
A (-2,4) e B (3,4)
![d = \sqrt{(3-(-2))^2+(4-4})^2} d = \sqrt{(3-(-2))^2+(4-4})^2}](https://tex.z-dn.net/?f=d+%3D+%5Csqrt%7B%283-%28-2%29%29%5E2%2B%284-4%7D%29%5E2%7D)
![d = \sqrt{(5)^2+(0})^2} d = \sqrt{(5)^2+(0})^2}](https://tex.z-dn.net/?f=d+%3D+%5Csqrt%7B%285%29%5E2%2B%280%7D%29%5E2%7D)
= 5
A (2,3) e B (5,1)
![d = \sqrt{(5-2)^2+(1-3)^2} d = \sqrt{(5-2)^2+(1-3)^2}](https://tex.z-dn.net/?f=d+%3D+%5Csqrt%7B%285-2%29%5E2%2B%281-3%29%5E2%7D)
![d = \sqrt{(3)^2+(-2)^2} d = \sqrt{(3)^2+(-2)^2}](https://tex.z-dn.net/?f=d+%3D+%5Csqrt%7B%283%29%5E2%2B%28-2%29%5E2%7D)
![d = \sqrt{9+4} d = \sqrt{9+4}](https://tex.z-dn.net/?f=d+%3D+%5Csqrt%7B9%2B4%7D)
![d = \sqrt{13} d = \sqrt{13}](https://tex.z-dn.net/?f=d+%3D+%5Csqrt%7B13%7D)
A (-2,4) e B (3,4)
A (2,3) e B (5,1)
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