Question

Me ajudem, por favor ❤️

Answer 1

$5^{ \frac{2}{7}}= \sqrt[7]{5^2} = \sqrt[7]{25}$
$2^{ \frac{3}{4}= \sqrt[4]{ 2^{3}}= \sqrt[4]{8}$
$\frac{1}{2}= 2^{-1}$
$(\sqrt{3}) ^{ \frac{4}{9}}= (3^{ \frac{1}{2}})^{ \frac{4}{9}}=3^\frac{1}{2}^\frac{4}{9}=3^\frac{4}{18}=3^\frac{2}{9}$
$9^\frac{1}{2}= \sqrt[2]{9^1}= \sqrt{9}=3$
$0^\frac{3}{8}=0$
$2^\frac{4}{3}= \sqrt[3]{2^4}= \sqrt[3]{16}$
$8^{0,6666....}=(dizma=0,666= \frac{6}{9}= \frac{2}{3})= 8^\frac{2}{3}= \sqrt[3]{ 8^{2}} = \sqrt[3]{64}=4$
$7^0^,^4= (0,4=4/10=\ \textgreater \ 2/5=\ \textgreater \ 7^{ \frac{2}{5}}= \sqrt[5]{ 7^{2}}= \sqrt[5]{49}$