Question

me ajudem por favor​

Answer 1

Resposta:

$d)\left[\begin{array}{ccc}-9&3&1\\-4&14&-7\end{array}\right]$

Explicação passo a passo:

$A^{t}=\left[\begin{array}{ccc}1&2&-1\\5&4&3\end{array}\right]\\\\B^{t}=\left[\begin{array}{ccc}-2&1&4\\-3&0&2\end{array}\right]\\\\A^{t}+B^{t}=\left[\begin{array}{ccc}1-2&2+1&-1+4\\5-3&4+0&3+2\end{array}\right]=\left[\begin{array}{ccc}-1&3&3\\2&4&5\end{array}\right]\\\\2\cdot C=\left[\begin{array}{ccc}8&0&2\\6&-10&12\end{array}\right]\\\\A^{t}+B^{t}-2\cdot C=\left[\begin{array}{ccc}-1&3&3\\2&4&5\end{array}\right]-\left[\begin{array}{ccc}8&0&2\\6&-10&12\end{array}\right]=$$\left[\begin{array}{ccc}-1-8&3-0&3-2\\2-6&4-(-10)&5-12\end{array}\right]=\left[\begin{array}{ccc}-9&3&1\\-4&14&-7\end{array}\right]$