Question

me ajudem por favor ;-;

5^(2x-1)=1/5

100^x=0,001

4^x=1

2^(x+3)=1/8

√(5^x )×25^(x+1)=0,2^(1-x)

(2/5)^(x+3)=(125/8)^(x-1)×0,4^(2x-3)

Answer 1

Explicação passo-a-passo:

b) 5^(2x - 1) = 1/5

5^(2x - 1) = 5^(-1)

2x - 1 = - 1

2x = - 1 + 1

2x = 0

x = 0

c) 100^x = 0,001

(10²)^x = 10^(-3)

10^2x = 10^(-3)

2x = - 3

x = - 3/2

d) 4^x = 1

x = 0

e) 2^(x + 3) = 1/8

2^(x + 3) = 1/2³

2^(x + 3) = 2^(-3)

x + 3 = - 3

x = - 3 - 3

x = - 6

f) √5^x • 25^(x + 1) = 0,2^(1 - x)

5^(x/2) • (5²)^(x + 1) = (2/10)^(1 - x)

5^(x/2) • 5^(2x + 2) = (1/5)^(1 - x)

5^[x/2 + (2x + 2)] = 5^[- (1 - x)]

5^[(x + 4x + 4)/2] = 5^(x - 1)

5^[(5x + 4)/2] = 5^(x - 1)

(5x + 4)/2 = x - 1

5x + 4 = 2(x - 1)

5x + 4 = 2x - 2

5x - 2x = - 2 - 4

3x = - 6

x = - 6/3

x = - 2