Matemática, perguntado por tuanigdutra, 6 meses atrás

Me ajudem por favor!

Anexos:

Soluções para a tarefa

Respondido por JohanLiebert
0

Resposta e explicação passo a passo:

4-\\\\a)\ \sqrt{\frac{3}{2}}=\frac{\sqrt{3}}{\sqrt{2}}=\frac{\sqrt{3}}{\sqrt{2}}\bullet\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{6}}{2}=\frac{2,449}{2} =1,2245\\\\b) \sqrt{\frac{2}{5}}=\frac{\sqrt{2}}{\sqrt{5}}=\frac{\sqrt{2}}{\sqrt{5}}\bullet\frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{10}}{5}=\frac{3,162}{5} =0,6324\\\\c)\ \sqrt{\frac{1}{2}}=\frac{\sqrt{1}}{\sqrt{2}}=\frac{\sqrt{1}}{\sqrt{2}}\bullet\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{2}=\frac{1,414}{2} =0,707

5-\\\\a)\ \frac{1}{\sqrt[5]{6^3}}=\frac{1}{\sqrt[5]{6^3}}\bullet\frac{\sqrt[5]{6^2}}{\sqrt[5]{6^2}}=\frac{\sqrt[5]{6^2}}{\sqrt[5]{6^5}}=\frac{\sqrt[5]{6^2}}{6}\\\\b)\ \frac{15}{\sqrt[3]{5}}=\frac{15}{\sqrt[3]{5}}\bullet\frac{\sqrt[3]{5^2}}{\sqrt[3]{5^2}}=\frac{15\sqrt[3]{5^2}}{\sqrt[3]{5^3}}=\frac{15\sqrt[3]{5^2}}{5}\\\\c)\ \frac{2}{\sqrt[9]{2^7}}=\frac{2}{\sqrt[9]{2^7}}\bullet\frac{\sqrt[9]{2^2}}{\sqrt[9]{2^2}}=\frac{2\sqrt[9]{2^2}}{\sqrt[9]{2^9}}=\frac{2\sqrt[9]{2^2}}{2}

d)\ \frac{6}{\sqrt[10]{3^5}}=\frac{6}{\sqrt[10]{3^5}}\bullet\frac{\sqrt[10]{3^5}}{\sqrt[10]{3^5}}=\frac{6\sqrt[10]{3^5}}{\sqrt[10]{3^{10}}}=\frac{6\sqrt[10]{3^5}}3}\\\\e)  \frac{4}{\sqrt[4]{8^3}}=\frac{4}{\sqrt[4]{8^3}}\bullet\frac{\sqrt[4]{8}}{\sqrt[4]{8}}=\frac{4\sqrt[4]{8}}{\sqrt[4]{8^4}}=\frac{4\sqrt[4]{8}}8}\\\\f)\  \frac{20}{\sqrt[11]{10^8}}=\frac{20}{\sqrt[11]{10^8}}\bullet\frac{\sqrt[11]{10^3}}{\sqrt[11]{10^3}}=\frac{20\sqrt[11]{10^3}}{\sqrt[11]{10^{11}}}=\frac{20\sqrt[11]{10^3}}{10}}

Perguntas interessantes