Question

Me ajudem Por favor.​

Answer 1

Resposta:

Explicação passo a passo:

$10)$

$a)$

$\sqrt{128a^{2}b^{3} }$

$128=2^{7}=2^{2}\:.\:2^{2}\:.\:2^{2}\:.\:2$

    $\sqrt{128a^{2}b^{3} }=$

     $\sqrt{2^{7} a^{2}b^{3} }=$

$\sqrt{2^{2}.2^{2}.2^{2}.2. a^{2}.b^{2}.b }=$

   $2.2.2.a.b\sqrt{2b} =$

       $8ab\sqrt{ab}$

$b)$

$2\sqrt[3]{7^{3}.\:y^{12} } =$

$Obs.:\:y^{12}=(y^{4})^{3}$

$2\sqrt[3]{7^{3}.\:y^{12} } =$

$2\sqrt[3]{7^{3}.\:(y^{4})^{3} } =$

$2\:.\:7.\:y^{4} =$

$14y^{4}$

$c)$

$\sqrt[3]{10^{6} }=$

$Obs.:\:10^{6}=(10^{2})^{3}$

 $\sqrt[3]{10^{6} }=$

$\sqrt[3]{(10^{2})^{3} } =$

   $10^{2} =$

   $100$

$11)$

$a)$

$N=\{0;1\}$

$b)$

$Z=\{-4;0;1\}$

$c)$

$\{-4\}$

$d)$

$Q=\{-2,3\:;\:-1/4\:;\:0,666...\}$

$12)$

$(a^{m})^{n}=a^{m.n}$

$(2^{4})^{8}=2^{32}$

$(4^{8})^{2}=4^{16}=(2^{2})^{16}=2^{32}$

$Portanto...$

$\frac{2^{32} }{2^{32} } =1$

$Resposta:(c)$