Question

me ajudem por favor
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Answer 1

Explicação passo a passo:

a)

$\frac{x+2}{3} =\frac{2x+1}{5} \\\\5x+10=6x+3\\5x-6x=3-10\\-1x=-7\\*-1\\1x=7$

b)

$\frac{4x}{6}-\frac{1}{2} \frac{x-2}{3}\\\\\frac{4x}{6}-\frac{1}{2}=\frac{4x-3}{6} \\ \frac{4x-3}{6} =\frac{x-2}{3} \\\\12x-9=6x-12\\12x-6x=-12+9\\6x=-3\\x=-3/6$

c)

$\frac{y-3}{4}+ \frac{y+1}{6} =\frac{y-1}{12}\\\\\frac{y-3}{4}+ \frac{y+1}{6}=\frac{(3y-9)+2y+2}{12} \\\\ \frac{(3y-9)+2y+2}{12}=\frac{y-1}{12}\\36y-108+24y+24=12y-12\\36y+24y-12y=108-24-12\\48y=72\\y=72/48$

d)

$4(x-2)=5-(\frac{x}{2}+4)\\4x-8=5-(\frac{x}{2}+4)\\\\\frac{x}{2}+ \frac{4}{1}=\frac{x+8}{2} \\\\4x(-2)=5-\frac{x+8}{2} \\\frac{5}{1}-\frac{x+8}{2}=\frac{10-(x+8)}{2} \\\frac{4x-8}{1} =\frac{10-(x+8)}{2} \\\\10-(x+8)=8x-16\\10-x-8=8x-16\\-x-8x=-16-10+8\\-9x=-18\\-1*\\9x=18\\x=18/9\\x=2$