Question

Me ajudem. POR FAVOR….

Answer 1

1))
a) √49=49^½
=> (7²)^½
=>(7)^2/2
=>7

b)
√81=81^½
=>(9²)^½
=>9^2/2
=>9

c )
√9/√25
{(3²)^½}/{(5²)^½}
=>3/5

d)
√81/√64
=>9/8

√1/√36
=>1/6


√169/√121
=>13/11