Question

Me ajudem por favor :(

Answer 1

Resposta:

A)2³x‐¹=32

2³x‐¹=2⁵

3x -1=5

3x =5+1

3=6

X=6

3

X= 2

B)7⁴x+3=49 decompondo logo ficará (7²)

7⁴×+3=7²

4x+3=2

4×=2-3

4x=-1

X= -1/4

C) 11²x+⁵= 1

11²x+⁵=11⁰

2x+5=0

2x=-5

X=- 5

2

S=- 5

2

D)2x²-x- 16=16

2x²-x-16=2⁴ => cancelar a base 2

X²=-X-16=4

X²-X-20=0

b/c=-1/-20= 4-5/4.(-5)

(X+4).(X-5)= 0

X=-4

X=5

E)3x²+2x=243

3(X²+2X)=3⁵ cancelar a bases 3

X²=+2X=5

X²=+2x-5=0

d²=4+20=24

d=2√6

X1=(-2+2√6)/2=-1+√6

X2=(-2-2√6)/2=-1-√6

F)5²x²+3x-2=1 deixando 1=5⁰

5x²X²-3X-2=5⁰

2x²-3x-2=0

2x²-3x-2=0 a=2 b=-3 c=- 2

d=b²-4ac

d=(-3)²-4(2).(-2)

d=9+16

d=25√d=5√25=5

X=- b+ √d /2a

X'= -(-3) +√25/2(2)

X'=+3+5/4

X'=8/4

X'= 2

e

X''=-(-3)+√25/2(4)

X"=+3-5/4

X"=-2/4

X"-1/2

V={-1/2,2}

G)81¹-³x=27

4(1-3x)=3 cancelar a base 3

3=3

4-12x=3

-12x=3-4

-12x=-1

X=1/12

H)7³x+⁴=49²x-3

7^3x+4=49^2x-3

7^3x+4=7^4x-6

3x=4=4Xx-6

4x-3x=4+6

X=10

Í)5³x-¹=( 1 )²x+3

25

5³x-¹=(1/5²)²x+3

5³X-¹= (5-²)²x+³

5X-¹= 5(-²).(²x+³)

5X³-¹= 5-4x-0

bases iguais iguale os exp.

3X-1=-4x-6

3x+4x=-6+1

7x=-5

X=-5/7