Question

me ajudem por favor.​

Answer 1

PS: eu tirei o (x) e coloquei (.) pq ficar mais facil pra mim, vc tbm pode colocar(.) ou (x) se vc quiser

Resposta:

a) $4^{2}$- $\sqrt{100}$+ ($2^{3}$-5)

16-10 (8-5)

16-10+3

6+3

9

b)30-($\sqrt{4}$+1$)^{2}$ +$2^{3}$

30-(2+1$)^{2}$+8

30-(3$)^{2}$+ 8

30-9+8

21+8

29

c)30+[$6^{2}$:(5-$\sqrt{9}$)+1]

30+[36:(5-3)+1

30+[36:2+1]

30+[18 +1]

30+19

49

d)20-[6-4.($\sqrt{100}$ -$3^{2}$)+1]

20-[6-4.(10-9)+1]

20-[6-4.1+1]

20-[6-4+1]

20-[7-4]

20-3

17

e)50+[$3^{3}$:(1+$\sqrt{4}$)+4.3]

50+[27:(1+2)+12]

50+[27:3 +12]

50+[9+12]

50+21

71

f)100-[$5^{2}$:(10-$\sqrt{25\\}$)+$2^{4}$.1]

100-[25:(10-5)+16.1]

100-[25:5+16]

100-[5+16]

100-21

79

g)[$4^{2}$+(5-3$)^{3}$]:($\sqrt{81}$-7

[16+(2$)^{3}$] :(9-7

[16+8]:(2$)^{3}$

24:8

3

h)$7^{2}$+2.[($\sqrt{9}$+1$)^{2}$-4.$1^{3}$]

49+2.[(3+1$)^{2}$-4.1]

49+2.[(4$)^{2}$-4]

49+2.[16-4]

49+2.12

49+24

73

i)25+{$3^{3$:9+[$3^{2}$.$\sqrt{25}$-3.($2^{3}$-$5^{1}$)]}

25+{27:9+[9.5-3.(8-5)]}

25+{3+[45-3.3]}

25+{3+[45-9]}

25+{3+36}

25+39

64