Matemática, perguntado por gabriell1808, 6 meses atrás

Me ajudem por favor

Anexos:

Soluções para a tarefa

Respondido por mceciliacastrop5luu9
1

Resposta:

6.a) 512, 320 e 448

b) 320, 800 e 160

7. a = 45 // b = 60 // y = 75

Explicação passo-a-passo:

6. a) x+y+z=1280\\\frac{x}{8} = \frac{y}{5} = \frac{z}{7} = k\\---------\\\frac{x}{8} = k\\x=8k\\---------\\\frac{y}{5} = k \\y = 5k\\---------\\\frac{z}{7}= k\\z= 7k\\---------\\8k+5k+7k = 1280\\20k = 1280\\k = 64\\x = 8*64 =512\\y = 5 * 64 = 320\\z = 7* 64 = 448

6. b) \frac{a}{\frac{1}{5}} + \frac{b}{\frac{1}{2}} + \frac{c}{\frac{1}{10}} = 1280\\\\\frac{a}{\frac{1}{5}} = k\\a * 5 = k\\a = \frac{k}{5}\\\\---------\\\frac{b}{\frac{1}{2}} = k\\b* 2 =k\\b = \frac{k}{2}\\---------\\\frac{c}{\frac{1}{10}} = k\\c*10 = k\\c = \frac{k}{10}\\----------\\\frac{k}{5}+\frac{k}{2}+\frac{k}{10} = 1280\\\frac{2k+5k+k}{10} =1280\\\frac{8k}{10}=1280\\8k = 12800\\k = 1600\\---------\\a = \frac{1600}{5} = 320\\b = \frac{1600}{2} = 800\\c = \frac{1600}{10} = 160

7. \frac{\alpha }{3} + \frac{\beta }{4} + \frac{y}{5} = 180\\---------\\\frac{\alpha}{3} = k\\\alpha = 3k\\---------\\\frac{\beta}{4} = k\\\beta = 4k\\---------\\\frac{y}{5} = k\\y = 5k\\---------\\3k+4k+5k = 180\\12k = 180\\k = 15\\---------\\\alpha = 3*15 = 45\\\beta = 4*15 = 60\\y = 5*15= 75

Espero que tenha ajudado.

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