Question

me ajudem por favor ​

Answer 1

Explicação passo-a-passo:

2.

$(3^6\cdot3^4)/(3^6/3^2)\\3^{6+4}/3^{6-2}\\3^{10}/3^4\\3^{10-4}\\3^6$

3.

$2^5\cdot2^{-3}=2^{5+(-3)}=2^2$

$(7^2)^{-3}=7^{2\cdot(-3)}=7^{-6}$

$10^{-1}\cdot10^{4}\cdot10^{-8}=10^{(-1)+4+(-8)}=10^{-5}$

$\frac{5^{3}}{5^{4}}=5^{3-4}=5^{-1}$

$4^{3}\div4^{-2}=4^{3-(-2)}=4^{3+2}=4^{5}$

4.

$\sqrt[3]{5^{2}} =5^{\frac{2}{3} }$

$\sqrt[]{3^{}} =3^{\frac{1}{2} }$

$\sqrt[]{10^{5}} =10^{\frac{5}{2} }$

$\sqrt[4]{2^{3}} =2^{\frac{3}{4} }$