Question

Me ajudem por favor ​

Answer 1

Resposta:

a) x² + 9x + 8 = 0

a = 1, b = 9, c = 8

Δ = b² - 4 . a . c

Δ = 9² - 4 . 1 . 8

Δ = 81 - 4 . 8

Δ = 81 - 32

Δ = 49

X = - b ± $\sqrt{Δ}$ / 2a

X = - 9 ± $\sqrt{49}$ / 2 . 1

X = - 9 ± 7 / 2 . 1

x¹ = - 9 + 7 / 2

x¹ = - 2 / 2

x¹ = - 1

x² = - 9 - 7 / 2

x² = - 16 / 2

x² = - 8

b) 9x² - 24x + 16

a = 9, b = - 24, c = 16

Δ = b² - 4 . a . c

Δ = ( - 24)² - 4 . 9 . 16

Δ = 576 - 36 . 16

Δ = 576 - 576

Δ = 0

X = - b ± $\sqrt{Δ}$ / 2a

X = - 576 ± $\sqrt{0}$ / 2 . 9

X = - 576 ± 0 / 18

x¹ = - 576 + 0 / 18

x¹ = - 576 / 18

x¹ = - 32

x² = - 576 - 0 / 18

x² = - 576 / 18

x² =  32