Question

Me ajudem por favor

Answer 1

Olá!

Vamos resolver!

a) $\sqrt[5]{2^{5} .x^{5} }$ =

$2^{5:5}$ · $x^{5:5}$ =

2 · x = 2x

b) $\sqrt[6]{a^{12}.b^{6} }$ =

$a^{12:6}$ · $b^{6:6}$ =

$a^{2}$ · b = $a^{2} b$

c) $\sqrt{\frac{5^{4} }{7^{8} } }$ =

$\frac{\sqrt{5^{4} } }{\sqrt{7^{8} } }$ =

$\frac{5^{4:2} }{7^{8:2} }$ =

$\frac{5^{2} }{7^{4} }$ = $\frac{25}{2401}$

Abraços!