Question

Me ajudem por favor!

Answer 1

$6\sqrt{48}-12\sqrt{48}+6\sqrt{108}-10\sqrt{27}=$

$-6\sqrt{48}+6\sqrt{108}-10\sqrt{27}=$

$-6\sqrt{16.3}+ 6\sqrt{36.3}-10 \sqrt{9.3}=$

$-6.4\sqrt{3}+6.6\sqrt{3}-10.3\sqrt{3}=$

$-24\sqrt{3}+36\sqrt{3}-30\sqrt{3}=$

$-18\sqrt{3}$