Question

Me ajudem por favor!!!!

Answer 1

Resposta:

a) 1

b) $\sqrt[3]{9}$

c) $2\sqrt[4]{108}$

d) $6$

Explicação passo-a-passo:

a) $\sqrt[6]{9^{6}}= 9^{\frac{6}{6} } = 9^{1}= 9$

b) $\sqrt[12]{9^{4}} = 9^{\frac{4}{12} }= 9^{\frac{1}{3}}=\sqrt[3]{9}$

c) $\sqrt[4]{12^{3}}= \sqrt[4]{1728} = \sqrt[4]{2^{4}.108 }= 2\sqrt[4]{108}$

d) $\sqrt[3]{^{216}} = \sqrt[3]{6^{3}} = 6^{\frac{3}{3} }= 6^{1}=6$