Question

ME AJUDEM POR FAVOR!!

Answer 1

Explicação passo-a-passo:

a) x² - 2x / 3x - 6 = 1

x² - 2x / 3x - 6 = 1, x ≠ 2

x (x - 2) / 3 (x - 2) = 1

x = 3, x ≠ 2

x = 3 -> resposta final da letra a

b) x + 4 / x - 2 + 1 = 10 + 2x / 5

x * 4 / x - 2 + 1 = 10 + 2x / 5, x ≠ 2

4x / x - 2 + 1 - 10 + 2x / 5 = 0

20x + 5 (x - 2) - (x - 2) * (10 + 2x) / 5 (x - 2) = 0

20x + 5x - 10 - (6x + 2x² - 20) / 5 (x - 2) = 0

20x + 5x - 10 - 6x - 2x² + 20 / 5 (x - 2) = 0 (remova os parenteses)

19x + 10 - 2x² / 5 (x - 2) = 0

19x + 10 - 2x² = 0

-2x² + 19x + 10 = 0

2x² - 19 - 10 = 0

2x² + x - 20x - 10 = 0

x (2x + 1) - 10 (2x + 1) = 0

(2x + 1) * (x - 10) = 0

2x + 1 = 0

x - 10 = 0

x = -1/2

x = 10

$x_{1}$ = -1/2, $x_{2}$ = 10 -> resposta final da letra b

c) 2 / x² - 1 + 1 / x + 1 = - 1

2 / (x - 1) * (x + 1) + 1 / x + 1 + 1

2 + x - 1 + (x - 1) * (x + 1) / (x - 1) * (x + 1)

2 + x - 1 + x² - 1 / (x - 1) * (x + 1)

0 + x + x² / (x - 1) * (x + 1)

x * (1 + x) / (x - 1) * ( x + 1)

x / x - 1 -> resposta final da letra c

d) x + 2 / 2 + 2 / x - 2 = - 1/2

(x - 2)(x + 2) + 4 = - (x - 2)

x² - 2x + 2x - 4 + 4 = -x + 2

x² + x - 2 = 0

x¹ = -2 e x² = -1 -> resposta final da letra d