Question

Me ajudem por favor!

Answer 1

Resposta:

a ) ( 3 - 2i ) - ( 1 + 3i ) =

3 - 2i - 1 - 3i = 0

- 5i = - 3 + 1

- 5i = - 2

5i = 2

i = 2/5

b) ( 9 + 4i ) + ( 5 - 2i ) + ( 8 - i ) =

9 + 4i + 5 - 2i + 8 - i = 0

4i - 2i - i = - 9 - 5 - 8

4i - 3i = - 22

i = - 22

c ) ( 6 + i ) • ( 6 - i ) =

( 6 × 6 ) + ( 6 × ( -i ) ) + ( i × 6 ) + ( i × ( - i ) = 0

36 + ( -6i ) + 6i + ( - i^2 ) = 0

36 - 6i + 6i - i^2 = 0

-i^2 = - 36

i^2 = 36

$i = \sqrt{36}$

i = 6

d) ( 2 - 3i ) • ( 2 - 3i ) =

( 2 × 2 ) - ( 2 × ( - 3i ) ) - ( -3i × 2 ) - ( 3i × 3i ) = 0

4 - ( - 6i ) - 6i - 9i^2 = 0

4 + 6i - 6i - 9i^2 = 0

- 9i^2 = - 4

- i^2 = - 4/9

i^2 = 4/9

$i = \sqrt{4 \div 9}$

$i = \sqrt{ {2}^{2} \div {3}^{2} }$

i= 2/3