Question

ME AJUDEM POR FAVOR
(2².3³.5)³: (3².5³.2)²

Answer 1

$\frac{(2^2.3^3.5)^3}{(3^2.5^3.2)^2}=\frac{2^6.3^9.5^3}{3^4.5^6.2^2}=\frac{2^4.3^5}{5^3}=\frac{16.243}{125}=\frac{3888}{125}=31,104$